10=2+37t-16t^2

Solution for 10=2+37t-16t^2 equation:

10=2+37t-16t^2

We move all terms to the left:

10-(2+37t-16t^2)=0

We get rid of parentheses

16t^2-37t-2+10=0

We add all the numbers together, and all the variables

16t^2-37t+8=0

a = 16; b = -37; c = +8;
Δ = b2-4ac
Δ = -372-4·16·8
Δ = 857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{857}}{2*16}=\frac{37-\sqrt{857}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{857}}{2*16}=\frac{37+\sqrt{857}}{32}
$